变态玩3P

[ 2007-07-06 11:00:35 | 作者: {$author:name$} ]

字体大小: 大 | 中 | 小

昨天在群里有个家伙出了个变态的题目“3男3女玩3P有多少种组合”

夜里1点,Ratboy用.net写出了过程。

在多人强烈要求下，Ratboy开放了源代码。
于是我换javascript重写了一下。

核心算法：

for (var m = 0; m <= 2; m++)
{
  for (var j = 0; j <= 1 ; j++)
  {
    var k = j + 1;
    for (k = k; k < women.length;k++ )
    {
    jieguo = men[m] + "、" + women[j] + "、" + women[k] + "\n";
    shuchu +=  jieguo;
    }
  }
}

for (var m= 0; m<= 2; m++)
{
  for (var j = 0; j <= 1 ; j++)
  {
    var k = j + 1;
    for (k = k; k < women.length;k++ )
    {
    jieguo = women[m] + "、" + men[j] + "、" + men[k] + "\n";
    shuchu +=  jieguo;
    }
  }
}

源代码：http://www.x2y2.com/files/3p.html

---11:30 update-
改进算法

for (var m = 0; m <= 2; m++)
{
  for (var j = 0; j <= 1 ; j++)
  {
    var k = j + 1;
    for (k = k; k < women.length;k++ )
    {
    jieguo = men[m] + "、" + women[j] + "、" + women[k] + "\n";
    shuchu +=  jieguo;
    jieguo = women[m] + "、" + men[j] + "、" + men[k] + "\n";
    shuchu +=  jieguo;
    }
  }
}